H-Weezy

H-Weezy

Problem:

Population: 1000

q2= .47 (Given)

q=?

p2=?

p=?

2pq=?

Steps:

1. The given was .47 which goes into the q2 value.

2. You then square root .47 to get q by itself, which results is .69

3. After you find q, you can find p. The way to do that is by finding out what number can be added to .69 to find 1. (p+q=1) Therefore it will be .31+.69=1

4. Once you figure out what p (.31) is, you need to find p2. To do that, you need to square the p variable which will result to .10.
5. To figure out 2pq, you need to substitute the p(.31) and the q(.69) and multiply 2(.31)(.69)=.43

Problem Solved:

Population: 1000

q2: .47 (homozygous recessive individual)

q: .69 (recessive allele frequency)

p2: .10 (homozygous dominant individual)

p: .31 (dominant allele frequency)

2pq: .43 (heterozygous individual)

Details:

To figure out the number of people for each variable, you need to multiply the variable x 1000. The first one is going to be .47(q2) x 1000=470. This represents that there are 470 individuals in the population that are homozygous recessive individuals. The next one is going to be .10(p2) x 1000= 100. That means that there are 100 homozygous dominant individuals in the population. The final one is to find the heterozygous individuals. To do that, .43(2pq) x 1000=430, which means there are 430 heterozygous individuals in the population.

   

Worm Lab

In the lab that we did during this past week had some interesting things,  especially when we had to figure out which worms pulse rate per minute were affected by stimulates, depressants, or it was neutral. To figure out which worms were affected by those three things, which were in containers labeled A, B, and C, I looked at my groups data table and the other groups data tables. I compared my groups data to the others and looked for common numbers. I then looked at the data tables and crossed out numbers that were too high or too low. When I did that I noticed that two of the of the three containers data were similar while one of the containers were a little different.  In the container labeled A, I noticed the data for it was in between both of the data for the containers like around 19 pulses per minute , so I assume that container A is neutral. Then in the data for table B, I noticed that it was the lowest pulse rate averaging to about 18 pulses per minute, so container B has depressants. Then for the final container, which is C, I realized that the data says that the pulse rate was the highest, which was about 30 pulses per minute. That means that container C is a stimulant. That is how I assumed which containers had the substances that I was looking for.

• In this picture it shows how I cancelled the numbers that were too high or too low.

Ecology Selfies

                                                          Bamboo

The first object that I took a picture with was a bamboo that my mom bought around a year ago. The reason I took a picture with the bamboo was because of how it looks. The leaves are very soft and the stems are smooth.

Feather

The second picture I took was with a feather. It took me a long time to find a feather to take a picture with and i was surprised that i found this one because it was so small. The feather is soft and is fun to make people sneeze with it.

 

Peach

The fruit that I took a picture with was a peach. Where I got the peach was at my house because I have two peach trees at my house. They are good and very sweet. Who knew that to do my homework I could just go in my front yard and pick out a fruit.